Base | Representation |
---|---|
bin | 111101001100000101… |
… | …1100111101110100111 |
3 | 110120011122102111012002 |
4 | 1322120023213232213 |
5 | 4123102430431043 |
6 | 140210525115515 |
7 | 12331161200621 |
oct | 1723013475647 |
9 | 416148374162 |
10 | 131402202023 |
11 | 50800132284 |
12 | 215723b8b9b |
13 | c511544681 |
14 | 65077d1c11 |
15 | 3640ee0bb8 |
hex | 1e982e7ba7 |
131402202023 has 2 divisors, whose sum is σ = 131402202024. Its totient is φ = 131402202022.
The previous prime is 131402202013. The next prime is 131402202047. The reversal of 131402202023 is 320202204131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131402202023 - 24 = 131402202007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131402201986 and 131402202004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131402202013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701101011 + 65701101012.
It is an arithmetic number, because the mean of its divisors is an integer number (65701101012).
Almost surely, 2131402202023 is an apocalyptic number.
131402202023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131402202023 is an equidigital number, since it uses as much as digits as its factorization.
131402202023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 131402202023 its reverse (320202204131), we get a palindrome (451604406154).
The spelling of 131402202023 in words is "one hundred thirty-one billion, four hundred two million, two hundred two thousand, twenty-three".
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