Base | Representation |
---|---|
bin | 11101111000001001110111… |
… | …010000101101100011101111 |
3 | 122020020221010100202020211111 |
4 | 131320021313100231203233 |
5 | 114210343231430322224 |
6 | 1143245203512132451 |
7 | 36451332522614305 |
oct | 3570116720554357 |
9 | 566227110666744 |
10 | 131402230323439 |
11 | 38961411406529 |
12 | 128a2771097127 |
13 | 584223c27996a |
14 | 2463c8aa9a275 |
15 | 102d118414d94 |
hex | 77827742d8ef |
131402230323439 has 2 divisors, whose sum is σ = 131402230323440. Its totient is φ = 131402230323438.
The previous prime is 131402230323367. The next prime is 131402230323473. The reversal of 131402230323439 is 934323032204131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131402230323439 - 29 = 131402230322927 is a prime.
It is a super-2 number, since 2×1314022303234392 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131402230323139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701115161719 + 65701115161720.
It is an arithmetic number, because the mean of its divisors is an integer number (65701115161720).
Almost surely, 2131402230323439 is an apocalyptic number.
131402230323439 is a deficient number, since it is larger than the sum of its proper divisors (1).
131402230323439 is an equidigital number, since it uses as much as digits as its factorization.
131402230323439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 40.
The spelling of 131402230323439 in words is "one hundred thirty-one trillion, four hundred two billion, two hundred thirty million, three hundred twenty-three thousand, four hundred thirty-nine".
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