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1314023210537 is a prime number
BaseRepresentation
bin10011000111110001111…
…000101111111000101001
311122121201112111100200012
4103013301320233320221
5133012104420214122
62443353125421305
7163635502000202
oct23076170577051
94577645440605
101314023210537
11467301933894
121927bb86a835
1396bb1471b5b
1447855b845a9
15242aa0e07e2
hex131f1e2fe29

1314023210537 has 2 divisors, whose sum is σ = 1314023210538. Its totient is φ = 1314023210536.

The previous prime is 1314023210519. The next prime is 1314023210567. The reversal of 1314023210537 is 7350123204131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1155670150441 + 158353060096 = 1075021^2 + 397936^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314023210537 - 28 = 1314023210281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1314023210567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657011605268 + 657011605269.

It is an arithmetic number, because the mean of its divisors is an integer number (657011605269).

Almost surely, 21314023210537 is an apocalyptic number.

It is an amenable number.

1314023210537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314023210537 is an equidigital number, since it uses as much as digits as its factorization.

1314023210537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 32.

Adding to 1314023210537 its reverse (7350123204131), we get a palindrome (8664146414668).

The spelling of 1314023210537 in words is "one trillion, three hundred fourteen billion, twenty-three million, two hundred ten thousand, five hundred thirty-seven".