Base | Representation |
---|---|
bin | 10011000111110001111… |
… | …000101111111000101001 |
3 | 11122121201112111100200012 |
4 | 103013301320233320221 |
5 | 133012104420214122 |
6 | 2443353125421305 |
7 | 163635502000202 |
oct | 23076170577051 |
9 | 4577645440605 |
10 | 1314023210537 |
11 | 467301933894 |
12 | 1927bb86a835 |
13 | 96bb1471b5b |
14 | 47855b845a9 |
15 | 242aa0e07e2 |
hex | 131f1e2fe29 |
1314023210537 has 2 divisors, whose sum is σ = 1314023210538. Its totient is φ = 1314023210536.
The previous prime is 1314023210519. The next prime is 1314023210567. The reversal of 1314023210537 is 7350123204131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1155670150441 + 158353060096 = 1075021^2 + 397936^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314023210537 - 28 = 1314023210281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314023210567) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657011605268 + 657011605269.
It is an arithmetic number, because the mean of its divisors is an integer number (657011605269).
Almost surely, 21314023210537 is an apocalyptic number.
It is an amenable number.
1314023210537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314023210537 is an equidigital number, since it uses as much as digits as its factorization.
1314023210537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 1314023210537 its reverse (7350123204131), we get a palindrome (8664146414668).
The spelling of 1314023210537 in words is "one trillion, three hundred fourteen billion, twenty-three million, two hundred ten thousand, five hundred thirty-seven".
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