Base | Representation |
---|---|
bin | 11101111000001001111100… |
… | …101011000010101111101100 |
3 | 122020020221100200120210101102 |
4 | 131320021330223002233230 |
5 | 114210343423201041134 |
6 | 1143245220514102232 |
7 | 36451335004403153 |
oct | 3570117453025754 |
9 | 566227320523342 |
10 | 131402321112044 |
11 | 38961458686334 |
12 | 128a279757a978 |
13 | 5842255016828 |
14 | 2463c98b7059a |
15 | 102d12139a37e |
hex | 77827cac2bec |
131402321112044 has 24 divisors (see below), whose sum is σ = 242057312629440. Its totient is φ = 62243100512784.
The previous prime is 131402321111939. The next prime is 131402321112047. The reversal of 131402321112044 is 440211123204131.
It is a junction number, because it is equal to n+sod(n) for n = 131402321111998 and 131402321112016.
It is not an unprimeable number, because it can be changed into a prime (131402321112047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62980967 + ... + 65033889.
It is an arithmetic number, because the mean of its divisors is an integer number (10085721359560).
Almost surely, 2131402321112044 is an apocalyptic number.
It is an amenable number.
131402321112044 is a deficient number, since it is larger than the sum of its proper divisors (110654991517396).
131402321112044 is a wasteful number, since it uses less digits than its factorization.
131402321112044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2895149 (or 2895147 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 131402321112044 its reverse (440211123204131), we get a palindrome (571613444316175).
The spelling of 131402321112044 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred twenty-one million, one hundred twelve thousand, forty-four".
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