Base | Representation |
---|---|
bin | 11101111000001001111101… |
… | …011101011011110100101111 |
3 | 122020020221101121102220222211 |
4 | 131320021331131123310233 |
5 | 114210343440041300332 |
6 | 1143245222105151251 |
7 | 36451335224602102 |
oct | 3570117535336457 |
9 | 566227347386884 |
10 | 131402334321967 |
11 | 38961465089125 |
12 | 128a279ba8b527 |
13 | 5842257990457 |
14 | 2463c9a80c739 |
15 | 102d122609447 |
hex | 77827d75bd2f |
131402334321967 has 2 divisors, whose sum is σ = 131402334321968. Its totient is φ = 131402334321966.
The previous prime is 131402334321961. The next prime is 131402334322031. The reversal of 131402334321967 is 769123433204131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131402334321967 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131402334321967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131402334321961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701167160983 + 65701167160984.
It is an arithmetic number, because the mean of its divisors is an integer number (65701167160984).
Almost surely, 2131402334321967 is an apocalyptic number.
131402334321967 is a deficient number, since it is larger than the sum of its proper divisors (1).
131402334321967 is an equidigital number, since it uses as much as digits as its factorization.
131402334321967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 49.
The spelling of 131402334321967 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred thirty-four million, three hundred twenty-one thousand, nine hundred sixty-seven".
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