Base | Representation |
---|---|
bin | 11101111000001010100101… |
… | …010101111110100100110101 |
3 | 122020021000010020112110001021 |
4 | 131320022211111332210311 |
5 | 114210401322341041142 |
6 | 1143245412331101141 |
7 | 36451360631256433 |
oct | 3570124525764465 |
9 | 566230106473037 |
10 | 131403003455797 |
11 | 38961778866297 |
12 | 128a2947ba17b1 |
13 | 58423334b3528 |
14 | 2463d2162dd53 |
15 | 102d161231267 |
hex | 7782a557e935 |
131403003455797 has 2 divisors, whose sum is σ = 131403003455798. Its totient is φ = 131403003455796.
The previous prime is 131403003455777. The next prime is 131403003455881. The reversal of 131403003455797 is 797554300304131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126669937791076 + 4733065664721 = 11254774^2 + 2175561^2 .
It is a cyclic number.
It is not a de Polignac number, because 131403003455797 - 235 = 131368643717429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131403003455777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701501727898 + 65701501727899.
It is an arithmetic number, because the mean of its divisors is an integer number (65701501727899).
Almost surely, 2131403003455797 is an apocalyptic number.
It is an amenable number.
131403003455797 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403003455797 is an equidigital number, since it uses as much as digits as its factorization.
131403003455797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4762800, while the sum is 52.
The spelling of 131403003455797 in words is "one hundred thirty-one trillion, four hundred three billion, three million, four hundred fifty-five thousand, seven hundred ninety-seven".
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