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131403031433243 is a prime number
BaseRepresentation
bin11101111000001010100111…
…000000101101000000011011
3122020021000012012011211212222
4131320022213000231000123
5114210401402021330433
61143245415210454255
736451361421132353
oct3570124700550033
9566230165154788
10131403031433243
1138961792635149
12128a295543438b
13584233922aa2b
142463d25233b63
15102d16390ab98
hex7782a702d01b

131403031433243 has 2 divisors, whose sum is σ = 131403031433244. Its totient is φ = 131403031433242.

The previous prime is 131403031433189. The next prime is 131403031433251. The reversal of 131403031433243 is 342334130304131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131403031433243 - 210 = 131403031432219 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403031433273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701515716621 + 65701515716622.

It is an arithmetic number, because the mean of its divisors is an integer number (65701515716622).

Almost surely, 2131403031433243 is an apocalyptic number.

131403031433243 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403031433243 is an equidigital number, since it uses as much as digits as its factorization.

131403031433243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 131403031433243 its reverse (342334130304131), we get a palindrome (473737161737374).

The spelling of 131403031433243 in words is "one hundred thirty-one trillion, four hundred three billion, thirty-one million, four hundred thirty-three thousand, two hundred forty-three".