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13140303341201 is a prime number
BaseRepresentation
bin1011111100110111011100…
…0111001110011010010001
31201112012102022222201220222
42333031313013032122101
53210242320123404301
643540323320042425
72524232652334361
oct277156707163221
951465368881828
1013140303341201
11420685373a643
121582819003415
13744182347c3a
14335dcba569a1
1517bc21d2731b
hexbf3771ce691

13140303341201 has 2 divisors, whose sum is σ = 13140303341202. Its totient is φ = 13140303341200.

The previous prime is 13140303341177. The next prime is 13140303341203. The reversal of 13140303341201 is 10214330304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12829470330625 + 310833010576 = 3581825^2 + 557524^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13140303341201 is a prime.

Together with 13140303341203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13140303341203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570151670600 + 6570151670601.

It is an arithmetic number, because the mean of its divisors is an integer number (6570151670601).

Almost surely, 213140303341201 is an apocalyptic number.

It is an amenable number.

13140303341201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140303341201 is an equidigital number, since it uses as much as digits as its factorization.

13140303341201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 13140303341201 its reverse (10214330304131), we get a palindrome (23354633645332).

The spelling of 13140303341201 in words is "thirteen trillion, one hundred forty billion, three hundred three million, three hundred forty-one thousand, two hundred one".