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13140305325542 = 270132774333769
BaseRepresentation
bin1011111100110111011100…
…1110110010110111100110
31201112012102110201112221002
42333031313032302313212
53210242321130404132
643540323430353302
72524233005240543
oct277156716626746
951465373645832
1013140305325542
11420685487549a
1215828197bb832
137441828911c5
14335dcc011bca
1517bc220ba262
hexbf3773b2de6

13140305325542 has 16 divisors (see below), whose sum is σ = 19714562904960. Its totient is φ = 6568784494272.

The previous prime is 13140305325487. The next prime is 13140305325599. The reversal of 13140305325542 is 24552350304131.

It is a junction number, because it is equal to n+sod(n) for n = 13140305325496 and 13140305325505.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 389106434 + ... + 389140202.

It is an arithmetic number, because the mean of its divisors is an integer number (1232160181560).

Almost surely, 213140305325542 is an apocalyptic number.

13140305325542 is a deficient number, since it is larger than the sum of its proper divisors (6574257579418).

13140305325542 is a wasteful number, since it uses less digits than its factorization.

13140305325542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68527.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 13140305325542 its reverse (24552350304131), we get a palindrome (37692655629673).

The spelling of 13140305325542 in words is "thirteen trillion, one hundred forty billion, three hundred five million, three hundred twenty-five thousand, five hundred forty-two".

Divisors: 1 2 7013 14026 27743 33769 55486 67538 194561659 236821997 389123318 473643994 936853367 1873706734 6570152662771 13140305325542