13140311304132 has 72 divisors (see below), whose sum is σ = 34332516953280. Its totient is φ = 4235276733120.

The previous prime is 13140311303993. The next prime is 13140311304137. The reversal of 13140311304132 is 23140311304131.

13140311304132 is a `hidden beast` number, since 1 + 3 + 1 + 40 + 311 + 304 + 1 + 3 + 2 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 13140311304096 and 13140311304105.

It is not an unprimeable number, because it can be changed into a prime (13140311304137) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 50580168 + ... + 50839295.

It is an arithmetic number, because the mean of its divisors is an integer number (476840513240).

Almost surely, 2^{13140311304132} is an apocalyptic number.

13140311304132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13140311304132 is an abundant number, since it is smaller than the sum of its proper divisors (21192205649148).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140311304132 is a wasteful number, since it uses less digits than its factorization.

13140311304132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101419593 (or 101419588 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 13140311304132 its reverse (23140311304131), we get a palindrome (36280622608263).

Subtracting 13140311304132 from its reverse (23140311304131), we obtain a palindrome (9999999999999).

The spelling of 13140311304132 in words is "thirteen trillion, one hundred forty billion, three hundred eleven million, three hundred four thousand, one hundred thirty-two".