13140311403281 has 2 divisors, whose sum is σ = 13140311403282. Its totient is φ = 13140311403280.

The previous prime is 13140311403211. The next prime is 13140311403371. The reversal of 13140311403281 is 18230411304131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12234989601025 + 905321802256 = 3497855^2 + 951484^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13140311403281 is a prime.

It is a super-2 number, since 2×13140311403281² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13140311403211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570155701640 + 6570155701641.

It is an arithmetic number, because the mean of its divisors is an integer number (6570155701641).

Almost surely, 2^{13140311403281} is an apocalyptic number.

It is an amenable number.

13140311403281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140311403281 is an equidigital number, since it uses as much as digits as its factorization.

13140311403281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 32.

The spelling of 13140311403281 in words is "thirteen trillion, one hundred forty billion, three hundred eleven million, four hundred three thousand, two hundred eighty-one".