Base | Representation |
---|---|
bin | 1011111100110111011111… |
… | …0000010100100010111010 |
3 | 1201112012110002021001202012 |
4 | 2333031313300110202322 |
5 | 3210242330403123414 |
6 | 43540324343005522 |
7 | 2524233143033546 |
oct | 277156760244272 |
9 | 51465402231665 |
10 | 13140314114234 |
11 | 420685982857a |
12 | 15828207398a2 |
13 | 74418464a608 |
14 | 335dcd25ca26 |
15 | 17bc22c5433e |
hex | bf377c148ba |
13140314114234 has 4 divisors (see below), whose sum is σ = 19710471171354. Its totient is φ = 6570157057116.
The previous prime is 13140314114227. The next prime is 13140314114273. The reversal of 13140314114234 is 43241141304131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8840899423225 + 4299414691009 = 2973365^2 + 2073503^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13140314114234.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285078528557 + ... + 3285078528560.
Almost surely, 213140314114234 is an apocalyptic number.
13140314114234 is a deficient number, since it is larger than the sum of its proper divisors (6570157057120).
13140314114234 is an equidigital number, since it uses as much as digits as its factorization.
13140314114234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6570157057119.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 13140314114234 its reverse (43241141304131), we get a palindrome (56381455418365).
The spelling of 13140314114234 in words is "thirteen trillion, one hundred forty billion, three hundred fourteen million, one hundred fourteen thousand, two hundred thirty-four".
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