Base | Representation |
---|---|
bin | 1011111100110111100001… |
… | …0111010000111111101111 |
3 | 1201112012110210110201222011 |
4 | 2333031320113100333233 |
5 | 3210242341011321221 |
6 | 43540325345502051 |
7 | 2524233325563613 |
oct | 277157027207757 |
9 | 51465423421864 |
10 | 13140324323311 |
11 | 4206864570829 |
12 | 1582824041927 |
13 | 7441867b33a3 |
14 | 335dd0759343 |
15 | 17bc23abe1e1 |
hex | bf3785d0fef |
13140324323311 has 2 divisors, whose sum is σ = 13140324323312. Its totient is φ = 13140324323310.
The previous prime is 13140324323263. The next prime is 13140324323327. The reversal of 13140324323311 is 11332342304131.
It is a strong prime.
It is an emirp because it is prime and its reverse (11332342304131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13140324323311 - 27 = 13140324323183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140324323611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570162161655 + 6570162161656.
It is an arithmetic number, because the mean of its divisors is an integer number (6570162161656).
Almost surely, 213140324323311 is an apocalyptic number.
13140324323311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140324323311 is an equidigital number, since it uses as much as digits as its factorization.
13140324323311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 13140324323311 its reverse (11332342304131), we get a palindrome (24472666627442).
The spelling of 13140324323311 in words is "thirteen trillion, one hundred forty billion, three hundred twenty-four million, three hundred twenty-three thousand, three hundred eleven".
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