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131403311242409 is a prime number
BaseRepresentation
bin11101111000001010110111…
…101100000101110010101001
3122020021000220200200121220102
4131320022313230011302221
5114210402440134224114
61143245503044035145
736451401356356463
oct3570126754056251
9566230820617812
10131403311242409
1138961916578998
12128a2a13092ab5
1358423821a959b
142463d5046d133
15102d17d27c2de
hex7782b7b05ca9

131403311242409 has 2 divisors, whose sum is σ = 131403311242410. Its totient is φ = 131403311242408.

The previous prime is 131403311242367. The next prime is 131403311242433. The reversal of 131403311242409 is 904242113304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129818222688400 + 1585088554009 = 11393780^2 + 1259003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131403311242409 is a prime.

It is a super-2 number, since 2×1314033112424092 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131403311242909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701655621204 + 65701655621205.

It is an arithmetic number, because the mean of its divisors is an integer number (65701655621205).

Almost surely, 2131403311242409 is an apocalyptic number.

It is an amenable number.

131403311242409 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403311242409 is an equidigital number, since it uses as much as digits as its factorization.

131403311242409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 38.

The spelling of 131403311242409 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred eleven million, two hundred forty-two thousand, four hundred nine".