Base | Representation |
---|---|
bin | 1011111100110111100101… |
… | …0011011100110101010001 |
3 | 1201112012111220011022010000 |
4 | 2333031321103130311101 |
5 | 3210242404031203213 |
6 | 43540331112000213 |
7 | 2524233606644220 |
oct | 277157123346521 |
9 | 51465456138100 |
10 | 13140340100433 |
11 | 4206872467377 |
12 | 1582829390069 |
13 | 744189b48670 |
14 | 335dd28a4cb7 |
15 | 17bc25188c73 |
hex | bf3794dcd51 |
13140340100433 has 160 divisors (see below), whose sum is σ = 25085353708800. Its totient is φ = 6667255494144.
The previous prime is 13140340100431. The next prime is 13140340100479. The reversal of 13140340100433 is 33400104304131.
13140340100433 is a `hidden beast` number, since 1 + 314 + 0 + 340 + 1 + 0 + 0 + 4 + 3 + 3 = 666.
It is not a de Polignac number, because 13140340100433 - 21 = 13140340100431 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13140340100397 and 13140340100406.
It is not an unprimeable number, because it can be changed into a prime (13140340100431) by changing a digit.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 57386910 + ... + 57615432.
It is an arithmetic number, because the mean of its divisors is an integer number (156783460680).
Almost surely, 213140340100433 is an apocalyptic number.
13140340100433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13140340100433 is a deficient number, since it is larger than the sum of its proper divisors (11945013608367).
13140340100433 is a wasteful number, since it uses less digits than its factorization.
13140340100433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228853 (or 228844 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 13140340100433 its reverse (33400104304131), we get a palindrome (46540444404564).
The spelling of 13140340100433 in words is "thirteen trillion, one hundred forty billion, three hundred forty million, one hundred thousand, four hundred thirty-three".
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