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13140340100431 is a prime number
BaseRepresentation
bin1011111100110111100101…
…0011011100110101001111
31201112012111220011022002221
42333031321103130311033
53210242404031203211
643540331112000211
72524233606644215
oct277157123346517
951465456138087
1013140340100431
114206872467375
121582829390067
13744189b4866b
14335dd28a4cb5
1517bc25188c71
hexbf3794dcd4f

13140340100431 has 2 divisors, whose sum is σ = 13140340100432. Its totient is φ = 13140340100430.

The previous prime is 13140340100417. The next prime is 13140340100479. The reversal of 13140340100431 is 13400104304131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13140340100431 - 213 = 13140340092239 is a prime.

It is a super-2 number, since 2×131403401004312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13140340100396 and 13140340100405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140340100731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570170050215 + 6570170050216.

It is an arithmetic number, because the mean of its divisors is an integer number (6570170050216).

Almost surely, 213140340100431 is an apocalyptic number.

13140340100431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140340100431 is an equidigital number, since it uses as much as digits as its factorization.

13140340100431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13140340100431 its reverse (13400104304131), we get a palindrome (26540444404562).

The spelling of 13140340100431 in words is "thirteen trillion, one hundred forty billion, three hundred forty million, one hundred thousand, four hundred thirty-one".