Base | Representation |
---|---|
bin | 1011111100110111100101… |
… | …0011011100110101001111 |
3 | 1201112012111220011022002221 |
4 | 2333031321103130311033 |
5 | 3210242404031203211 |
6 | 43540331112000211 |
7 | 2524233606644215 |
oct | 277157123346517 |
9 | 51465456138087 |
10 | 13140340100431 |
11 | 4206872467375 |
12 | 1582829390067 |
13 | 744189b4866b |
14 | 335dd28a4cb5 |
15 | 17bc25188c71 |
hex | bf3794dcd4f |
13140340100431 has 2 divisors, whose sum is σ = 13140340100432. Its totient is φ = 13140340100430.
The previous prime is 13140340100417. The next prime is 13140340100479. The reversal of 13140340100431 is 13400104304131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13140340100431 - 213 = 13140340092239 is a prime.
It is a super-2 number, since 2×131403401004312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13140340100396 and 13140340100405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140340100731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570170050215 + 6570170050216.
It is an arithmetic number, because the mean of its divisors is an integer number (6570170050216).
Almost surely, 213140340100431 is an apocalyptic number.
13140340100431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140340100431 is an equidigital number, since it uses as much as digits as its factorization.
13140340100431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13140340100431 its reverse (13400104304131), we get a palindrome (26540444404562).
The spelling of 13140340100431 in words is "thirteen trillion, one hundred forty billion, three hundred forty million, one hundred thousand, four hundred thirty-one".
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