Search a number
-
+
13140343221281 is a prime number
BaseRepresentation
bin1011111100110111100101…
…1111010110110000100001
31201112012112010000212002222
42333031321133112300201
53210242410331040111
643540331302520425
72524233645323003
oct277157137266041
951465463025088
1013140343221281
1142068741a9091
12158282a436115
1374418a69c013
14335dd3078373
1517bc255a37db
hexbf3797d6c21

13140343221281 has 2 divisors, whose sum is σ = 13140343221282. Its totient is φ = 13140343221280.

The previous prime is 13140343221197. The next prime is 13140343221353. The reversal of 13140343221281 is 18212234304131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13134890875681 + 5452345600 = 3624209^2 + 73840^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140343221281 - 222 = 13140339026977 is a prime.

It is a super-2 number, since 2×131403432212812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13140343251281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570171610640 + 6570171610641.

It is an arithmetic number, because the mean of its divisors is an integer number (6570171610641).

Almost surely, 213140343221281 is an apocalyptic number.

It is an amenable number.

13140343221281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140343221281 is an equidigital number, since it uses as much as digits as its factorization.

13140343221281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 13140343221281 in words is "thirteen trillion, one hundred forty billion, three hundred forty-three million, two hundred twenty-one thousand, two hundred eighty-one".