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131403432230513 is a prime number
BaseRepresentation
bin11101111000001010111110…
…111001100111111001110001
3122020021001020010100110101022
4131320022332321213321301
5114210403212122334023
61143245523045145225
736451404355634462
oct3570127671477161
9566231203313338
10131403432230513
11389619788a5063
12128a2a476bb215
1358423a128b191
142463d62564d69
15102d188bca7c8
hex7782bee67e71

131403432230513 has 2 divisors, whose sum is σ = 131403432230514. Its totient is φ = 131403432230512.

The previous prime is 131403432230503. The next prime is 131403432230519. The reversal of 131403432230513 is 315032234304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86429616343009 + 44973815887504 = 9296753^2 + 6706252^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403432230513 - 26 = 131403432230449 is a prime.

It is not a weakly prime, because it can be changed into another prime (131403432230519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701716115256 + 65701716115257.

It is an arithmetic number, because the mean of its divisors is an integer number (65701716115257).

Almost surely, 2131403432230513 is an apocalyptic number.

It is an amenable number.

131403432230513 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403432230513 is an equidigital number, since it uses as much as digits as its factorization.

131403432230513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 131403432230513 its reverse (315032234304131), we get a palindrome (446435666534644).

The spelling of 131403432230513 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-two million, two hundred thirty thousand, five hundred thirteen".