Base | Representation |
---|---|
bin | 11101111000001010111110… |
… | …111001100111111001100111 |
3 | 122020021001020010100110100221 |
4 | 131320022332321213321213 |
5 | 114210403212122334003 |
6 | 1143245523045145211 |
7 | 36451404355634446 |
oct | 3570127671477147 |
9 | 566231203313327 |
10 | 131403432230503 |
11 | 389619788a5054 |
12 | 128a2a476bb207 |
13 | 58423a128b184 |
14 | 2463d62564d5d |
15 | 102d188bca7bd |
hex | 7782bee67e67 |
131403432230503 has 2 divisors, whose sum is σ = 131403432230504. Its totient is φ = 131403432230502.
The previous prime is 131403432230453. The next prime is 131403432230513. The reversal of 131403432230503 is 305032234304131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131403432230503 - 225 = 131403398676071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131403432230513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701716115251 + 65701716115252.
It is an arithmetic number, because the mean of its divisors is an integer number (65701716115252).
Almost surely, 2131403432230503 is an apocalyptic number.
131403432230503 is a deficient number, since it is larger than the sum of its proper divisors (1).
131403432230503 is an equidigital number, since it uses as much as digits as its factorization.
131403432230503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 131403432230503 its reverse (305032234304131), we get a palindrome (436435666534634).
The spelling of 131403432230503 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty-two million, two hundred thirty thousand, five hundred three".
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