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13140345155401 is a prime number
BaseRepresentation
bin1011111100110111100110…
…0110101110111101001001
31201112012112020200010020001
42333031321212232331021
53210242411324433101
643540331412203001
72524234000626562
oct277157146567511
951465466603201
1013140345155401
1142068752aa232
12158282b009461
1374418abc8479
14335dd341d169
1517bc25836901
hexbf3799aef49

13140345155401 has 2 divisors, whose sum is σ = 13140345155402. Its totient is φ = 13140345155400.

The previous prime is 13140345155321. The next prime is 13140345155407. The reversal of 13140345155401 is 10455154304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11470109430025 + 1670235725376 = 3386755^2 + 1292376^2 .

It is an emirp because it is prime and its reverse (10455154304131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13140345155401 - 229 = 13139808284489 is a prime.

It is not a weakly prime, because it can be changed into another prime (13140345155407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570172577700 + 6570172577701.

It is an arithmetic number, because the mean of its divisors is an integer number (6570172577701).

Almost surely, 213140345155401 is an apocalyptic number.

It is an amenable number.

13140345155401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140345155401 is an equidigital number, since it uses as much as digits as its factorization.

13140345155401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 13140345155401 its reverse (10455154304131), we get a palindrome (23595499459532).

The spelling of 13140345155401 in words is "thirteen trillion, one hundred forty billion, three hundred forty-five million, one hundred fifty-five thousand, four hundred one".