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13140345155321 is a prime number
BaseRepresentation
bin1011111100110111100110…
…0110101110111011111001
31201112012112020200010010002
42333031321212232323321
53210242411324432241
643540331412202345
72524234000626416
oct277157146567371
951465466603102
1013140345155321
1142068752aa16a
12158282b0093b5
1374418abc8417
14335dd341d10d
1517bc2583689b
hexbf3799aeef9

13140345155321 has 2 divisors, whose sum is σ = 13140345155322. Its totient is φ = 13140345155320.

The previous prime is 13140345155297. The next prime is 13140345155401. The reversal of 13140345155321 is 12355154304131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11967967275625 + 1172377879696 = 3459475^2 + 1082764^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140345155321 - 242 = 8742298644217 is a prime.

It is a super-2 number, since 2×131403451553212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13140345155621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570172577660 + 6570172577661.

It is an arithmetic number, because the mean of its divisors is an integer number (6570172577661).

Almost surely, 213140345155321 is an apocalyptic number.

It is an amenable number.

13140345155321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140345155321 is an equidigital number, since it uses as much as digits as its factorization.

13140345155321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 13140345155321 its reverse (12355154304131), we get a palindrome (25495499459452).

The spelling of 13140345155321 in words is "thirteen trillion, one hundred forty billion, three hundred forty-five million, one hundred fifty-five thousand, three hundred twenty-one".