Base | Representation |
---|---|
bin | 11101111000001011100011… |
… | …010000010000100100001011 |
3 | 122020021002210122000021102010 |
4 | 131320023203100100210023 |
5 | 114210410434242102021 |
6 | 1143250103353511003 |
7 | 36451425443053110 |
oct | 3570134320204413 |
9 | 566232718007363 |
10 | 131404042144011 |
11 | 389621611040aa |
12 | 128a2b97a12463 |
13 | 584246a748140 |
14 | 2463dbd56c907 |
15 | 102d1c2505976 |
hex | 7782e341090b |
131404042144011 has 64 divisors (see below), whose sum is σ = 232629917442048. Its totient is φ = 64003998210048.
The previous prime is 131404042143961. The next prime is 131404042144013. The reversal of 131404042144011 is 110441240404131.
It is not a de Polignac number, because 131404042144011 - 29 = 131404042143499 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131404042144011.
It is not an unprimeable number, because it can be changed into a prime (131404042144013) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 266864731 + ... + 267356676.
It is an arithmetic number, because the mean of its divisors is an integer number (3634842460032).
Almost surely, 2131404042144011 is an apocalyptic number.
131404042144011 is a deficient number, since it is larger than the sum of its proper divisors (101225875298037).
131404042144011 is a wasteful number, since it uses less digits than its factorization.
131404042144011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 534221500.
The product of its (nonzero) digits is 6144, while the sum is 30.
Adding to 131404042144011 its reverse (110441240404131), we get a palindrome (241845282548142).
The spelling of 131404042144011 in words is "one hundred thirty-one trillion, four hundred four billion, forty-two million, one hundred forty-four thousand, eleven".
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