Search a number
-
+
1314045350131 = 6012186431531
BaseRepresentation
bin10011000111110011001…
…101001101000011110011
311122121210002011011111011
4103013303031031003303
5133012131102201011
62443355240131351
7163636161120133
oct23076315150363
94577702134434
101314045350131
11467313385678
12192807166b57
1396bb5c240c7
1447858aa8ac3
15242ac015621
hex131f334d0f3

1314045350131 has 4 divisors (see below), whose sum is σ = 1316231782264. Its totient is φ = 1311858918000.

The previous prime is 1314045350071. The next prime is 1314045350179. The reversal of 1314045350131 is 1310535404131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314045350131 - 29 = 1314045349619 is a prime.

It is a super-2 number, since 2×13140453501312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1314045350093 and 1314045350102.

It is not an unprimeable number, because it can be changed into a prime (1314045359131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1093215165 + ... + 1093216366.

It is an arithmetic number, because the mean of its divisors is an integer number (329057945566).

Almost surely, 21314045350131 is an apocalyptic number.

1314045350131 is a deficient number, since it is larger than the sum of its proper divisors (2186432133).

1314045350131 is an equidigital number, since it uses as much as digits as its factorization.

1314045350131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2186432132.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 1314045350131 in words is "one trillion, three hundred fourteen billion, forty-five million, three hundred fifty thousand, one hundred thirty-one".

Divisors: 1 601 2186431531 1314045350131