Base | Representation |
---|---|
bin | 10011000111110011001… |
… | …101001101000100100011 |
3 | 11122121210002011011112221 |
4 | 103013303031031010203 |
5 | 133012131102201204 |
6 | 2443355240131511 |
7 | 163636161120232 |
oct | 23076315150443 |
9 | 4577702134487 |
10 | 1314045350179 |
11 | 467313385711 |
12 | 192807166b97 |
13 | 96bb5c24133 |
14 | 47858aa8b19 |
15 | 242ac015654 |
hex | 131f334d123 |
1314045350179 has 2 divisors, whose sum is σ = 1314045350180. Its totient is φ = 1314045350178.
The previous prime is 1314045350071. The next prime is 1314045350197. The reversal of 1314045350179 is 9710535404131.
Together with next prime (1314045350197) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (9710535404131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1314045350179 - 217 = 1314045219107 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314045350279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657022675089 + 657022675090.
It is an arithmetic number, because the mean of its divisors is an integer number (657022675090).
Almost surely, 21314045350179 is an apocalyptic number.
1314045350179 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314045350179 is an equidigital number, since it uses as much as digits as its factorization.
1314045350179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 1314045350179 in words is "one trillion, three hundred fourteen billion, forty-five million, three hundred fifty thousand, one hundred seventy-nine".
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