Base | Representation |
---|---|
bin | 10011000111110011001… |
… | …101001101000010110111 |
3 | 11122121210002011011101221 |
4 | 103013303031031002313 |
5 | 133012131102200241 |
6 | 2443355240131211 |
7 | 163636161120016 |
oct | 23076315150267 |
9 | 4577702134357 |
10 | 1314045350071 |
11 | 467313385623 |
12 | 192807166b07 |
13 | 96bb5c2407c |
14 | 47858aa8a7d |
15 | 242ac0155d1 |
hex | 131f334d0b7 |
1314045350071 has 2 divisors, whose sum is σ = 1314045350072. Its totient is φ = 1314045350070.
The previous prime is 1314045350053. The next prime is 1314045350179. The reversal of 1314045350071 is 1700535404131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314045350071 - 227 = 1313911132343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314045350011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657022675035 + 657022675036.
It is an arithmetic number, because the mean of its divisors is an integer number (657022675036).
Almost surely, 21314045350071 is an apocalyptic number.
1314045350071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314045350071 is an equidigital number, since it uses as much as digits as its factorization.
1314045350071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 34.
The spelling of 1314045350071 in words is "one trillion, three hundred fourteen billion, forty-five million, three hundred fifty thousand, seventy-one".
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