Base | Representation |
---|---|
bin | 10011000111110011010… |
… | …000100111011001010101 |
3 | 11122121210010211121020121 |
4 | 103013303100213121111 |
5 | 133012131314310222 |
6 | 2443355311231541 |
7 | 163636201533343 |
oct | 23076320473125 |
9 | 4577703747217 |
10 | 1314046244437 |
11 | 467313936573 |
12 | 1928075185b1 |
13 | 96bb6178194 |
14 | 47858c5c993 |
15 | 242ac1405c7 |
hex | 131f3427655 |
1314046244437 has 2 divisors, whose sum is σ = 1314046244438. Its totient is φ = 1314046244436.
The previous prime is 1314046244411. The next prime is 1314046244471. The reversal of 1314046244437 is 7344426404131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1275079089636 + 38967154801 = 1129194^2 + 197401^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314046244437 - 215 = 1314046211669 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1314046244393 and 1314046244402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314046244837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657023122218 + 657023122219.
It is an arithmetic number, because the mean of its divisors is an integer number (657023122219).
Almost surely, 21314046244437 is an apocalyptic number.
It is an amenable number.
1314046244437 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314046244437 is an equidigital number, since it uses as much as digits as its factorization.
1314046244437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 774144, while the sum is 43.
The spelling of 1314046244437 in words is "one trillion, three hundred fourteen billion, forty-six million, two hundred forty-four thousand, four hundred thirty-seven".
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