Base | Representation |
---|---|
bin | 10011000111110100000… |
… | …100010100000100100101 |
3 | 11122121211002100010112222 |
4 | 103013310010110010211 |
5 | 133012143301444043 |
6 | 2443400513522125 |
7 | 163636424656463 |
oct | 23076404240445 |
9 | 4577732303488 |
10 | 1314059796773 |
11 | 467320552649 |
12 | 19280bb73345 |
13 | 96bb8c11909 |
14 | 4785a989833 |
15 | 242ad41ad68 |
hex | 131f4114125 |
1314059796773 has 2 divisors, whose sum is σ = 1314059796774. Its totient is φ = 1314059796772.
The previous prime is 1314059796641. The next prime is 1314059796787. The reversal of 1314059796773 is 3776979504131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 703984765444 + 610075031329 = 839038^2 + 781073^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314059796773 - 210 = 1314059795749 is a prime.
It is a super-2 number, since 2×13140597967732 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314059796073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657029898386 + 657029898387.
It is an arithmetic number, because the mean of its divisors is an integer number (657029898387).
Almost surely, 21314059796773 is an apocalyptic number.
It is an amenable number.
1314059796773 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314059796773 is an equidigital number, since it uses as much as digits as its factorization.
1314059796773 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30005640, while the sum is 62.
The spelling of 1314059796773 in words is "one trillion, three hundred fourteen billion, fifty-nine million, seven hundred ninety-six thousand, seven hundred seventy-three".
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