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1314059796773 is a prime number
BaseRepresentation
bin10011000111110100000…
…100010100000100100101
311122121211002100010112222
4103013310010110010211
5133012143301444043
62443400513522125
7163636424656463
oct23076404240445
94577732303488
101314059796773
11467320552649
1219280bb73345
1396bb8c11909
144785a989833
15242ad41ad68
hex131f4114125

1314059796773 has 2 divisors, whose sum is σ = 1314059796774. Its totient is φ = 1314059796772.

The previous prime is 1314059796641. The next prime is 1314059796787. The reversal of 1314059796773 is 3776979504131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 703984765444 + 610075031329 = 839038^2 + 781073^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314059796773 - 210 = 1314059795749 is a prime.

It is a super-2 number, since 2×13140597967732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314059796073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657029898386 + 657029898387.

It is an arithmetic number, because the mean of its divisors is an integer number (657029898387).

Almost surely, 21314059796773 is an apocalyptic number.

It is an amenable number.

1314059796773 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314059796773 is an equidigital number, since it uses as much as digits as its factorization.

1314059796773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30005640, while the sum is 62.

The spelling of 1314059796773 in words is "one trillion, three hundred fourteen billion, fifty-nine million, seven hundred ninety-six thousand, seven hundred seventy-three".