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1314060123012 = 22371319158710733
BaseRepresentation
bin10011000111110100000…
…101100011101110000100
311122121211002221201001220
4103013310011203232010
5133012143342414022
62443400524520340
7163636430515560
oct23076405435604
94577732851056
101314060123012
1146732075576a
121928100b00b0
1396bb8cc7260
144785aa326a0
15242ad48285c
hex131f4163b84

1314060123012 has 192 divisors, whose sum is σ = 3800285282304. Its totient is φ = 344131453440.

The previous prime is 1314060123011. The next prime is 1314060123017. The reversal of 1314060123012 is 2103210604131.

It is a happy number.

It is a super-3 number, since 3×13140601230123 (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1314060123011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 122426398 + ... + 122437130.

It is an arithmetic number, because the mean of its divisors is an integer number (19793152512).

Almost surely, 21314060123012 is an apocalyptic number.

1314060123012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1314060123012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1900142641152).

1314060123012 is an abundant number, since it is smaller than the sum of its proper divisors (2486225159292).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314060123012 is a wasteful number, since it uses less digits than its factorization.

1314060123012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11538 (or 11536 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1314060123012 its reverse (2103210604131), we get a palindrome (3417270727143).

The spelling of 1314060123012 in words is "one trillion, three hundred fourteen billion, sixty million, one hundred twenty-three thousand, twelve".