1314100241221 has 2 divisors, whose sum is σ = 1314100241222. Its totient is φ = 1314100241220.

The previous prime is 1314100241183. The next prime is 1314100241227. The reversal of 1314100241221 is 1221420014131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 982306960996 + 331793280225 = 991114^2 + 576015^2 .

It is an emirp because it is prime and its reverse (1221420014131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314100241221 - 2²³ = 1314091852613 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1314100241192 and 1314100241201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314100241227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050120610 + 657050120611.

It is an arithmetic number, because the mean of its divisors is an integer number (657050120611).

Almost surely, 2^{1314100241221} is an apocalyptic number.

It is an amenable number.

1314100241221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314100241221 is an equidigital number, since it uses as much as digits as its factorization.

1314100241221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1314100241221 its reverse (1221420014131), we get a palindrome (2535520255352).

The spelling of 1314100241221 in words is "one trillion, three hundred fourteen billion, one hundred million, two hundred forty-one thousand, two hundred twenty-one".