131410031 has 2 divisors, whose sum is σ = 131410032. Its totient is φ = 131410030.

The previous prime is 131410009. The next prime is 131410039. The reversal of 131410031 is 130014131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131410031 - 2²² = 127215727 is a prime.

It is a super-2 number, since 2×131410031² = 34537192494841922, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131409988 and 131410015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131410039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705015 + 65705016.

It is an arithmetic number, because the mean of its divisors is an integer number (65705016).

Almost surely, 2^131410031 is an apocalyptic number.

131410031 is a deficient number, since it is larger than the sum of its proper divisors (1).

131410031 is an equidigital number, since it uses as much as digits as its factorization.

131410031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 131410031 is about 11463.4214351563. The cubic root of 131410031 is about 508.4046404552.

Adding to 131410031 its reverse (130014131), we get a palindrome (261424162).

It can be divided in two parts, 1314100 and 31, that added together give a palindrome (1314131).

The spelling of 131410031 in words is "one hundred thirty-one million, four hundred ten thousand, thirty-one".