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1314100450181 is a prime number
BaseRepresentation
bin10011000111110110011…
…111011001001110000101
311122121220220211112112202
4103013312133121032011
5133012234203401211
62443404525124245
7163640430345521
oct23076637311605
94577826745482
101314100450181
1146734149a102
121928216b9685
1396bc447699c
144786212cd81
15242b1c9b53b
hex131f67d9385

1314100450181 has 2 divisors, whose sum is σ = 1314100450182. Its totient is φ = 1314100450180.

The previous prime is 1314100450141. The next prime is 1314100450199. The reversal of 1314100450181 is 1810540014131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 899794530625 + 414305919556 = 948575^2 + 643666^2 .

It is an emirp because it is prime and its reverse (1810540014131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314100450181 - 214 = 1314100433797 is a prime.

It is a super-2 number, since 2×13141004501812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314100450141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050225090 + 657050225091.

It is an arithmetic number, because the mean of its divisors is an integer number (657050225091).

Almost surely, 21314100450181 is an apocalyptic number.

It is an amenable number.

1314100450181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314100450181 is an equidigital number, since it uses as much as digits as its factorization.

1314100450181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 29.

The spelling of 1314100450181 in words is "one trillion, three hundred fourteen billion, one hundred million, four hundred fifty thousand, one hundred eighty-one".