Base | Representation |
---|---|
bin | 10011000111110110011… |
… | …111011001010001110001 |
3 | 11122121220220211112212111 |
4 | 103013312133121101301 |
5 | 133012234203403132 |
6 | 2443404525125321 |
7 | 163640430346306 |
oct | 23076637312161 |
9 | 4577826745774 |
10 | 1314100450417 |
11 | 46734149a2a7 |
12 | 1928216b9841 |
13 | 96bc4476b21 |
14 | 4786212d0ad |
15 | 242b1c9b647 |
hex | 131f67d9471 |
1314100450417 has 2 divisors, whose sum is σ = 1314100450418. Its totient is φ = 1314100450416.
The previous prime is 1314100450373. The next prime is 1314100450427. The reversal of 1314100450417 is 7140540014131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 887983944241 + 426116506176 = 942329^2 + 652776^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314100450417 - 215 = 1314100417649 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314100450427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050225208 + 657050225209.
It is an arithmetic number, because the mean of its divisors is an integer number (657050225209).
Almost surely, 21314100450417 is an apocalyptic number.
It is an amenable number.
1314100450417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314100450417 is an equidigital number, since it uses as much as digits as its factorization.
1314100450417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 1314100450417 its reverse (7140540014131), we get a palindrome (8454640464548).
The spelling of 1314100450417 in words is "one trillion, three hundred fourteen billion, one hundred million, four hundred fifty thousand, four hundred seventeen".
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