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1314100450373 is a prime number
BaseRepresentation
bin10011000111110110011…
…111011001010001000101
311122121220220211112210212
4103013312133121101011
5133012234203402443
62443404525125205
7163640430346214
oct23076637312105
94577826745725
101314100450373
1146734149a267
121928216b9805
1396bc4476ab9
144786212d07b
15242b1c9b618
hex131f67d9445

1314100450373 has 2 divisors, whose sum is σ = 1314100450374. Its totient is φ = 1314100450372.

The previous prime is 1314100450363. The next prime is 1314100450417. The reversal of 1314100450373 is 3730540014131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1054878947329 + 259221503044 = 1027073^2 + 509138^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314100450373 - 26 = 1314100450309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314100450363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050225186 + 657050225187.

It is an arithmetic number, because the mean of its divisors is an integer number (657050225187).

Almost surely, 21314100450373 is an apocalyptic number.

It is an amenable number.

1314100450373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314100450373 is an equidigital number, since it uses as much as digits as its factorization.

1314100450373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 32.

The spelling of 1314100450373 in words is "one trillion, three hundred fourteen billion, one hundred million, four hundred fifty thousand, three hundred seventy-three".