Base | Representation |
---|---|
bin | 10011000111110110100… |
… | …101111000011110001001 |
3 | 11122121221001000221200212 |
4 | 103013312211320132021 |
5 | 133012240122313144 |
6 | 2443405025410505 |
7 | 163640450661362 |
oct | 23076645703611 |
9 | 4577831027625 |
10 | 1314102151049 |
11 | 467342450a86 |
12 | 192822199a35 |
13 | 96bc4920c0c |
14 | 47862452b69 |
15 | 242b1ed549e |
hex | 131f6978789 |
1314102151049 has 2 divisors, whose sum is σ = 1314102151050. Its totient is φ = 1314102151048.
The previous prime is 1314102151009. The next prime is 1314102151079. The reversal of 1314102151049 is 9401512014131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 946472145424 + 367630005625 = 972868^2 + 606325^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314102151049 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314102151009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657051075524 + 657051075525.
It is an arithmetic number, because the mean of its divisors is an integer number (657051075525).
Almost surely, 21314102151049 is an apocalyptic number.
It is an amenable number.
1314102151049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314102151049 is an equidigital number, since it uses as much as digits as its factorization.
1314102151049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 1314102151049 in words is "one trillion, three hundred fourteen billion, one hundred two million, one hundred fifty-one thousand, forty-nine".
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