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13141030444103 is a prime number
BaseRepresentation
bin1011111100111010001001…
…1100111001110001000111
31201112021022000011101121002
42333032202130321301013
53210300312243202403
643540523412243515
72524256661530042
oct277164234716107
951467260141532
1013141030444103
114207097110831
1215829a061059b
13744269b86743
1433605a447c59
1517bc65aa0188
hexbf3a2739c47

13141030444103 has 2 divisors, whose sum is σ = 13141030444104. Its totient is φ = 13141030444102.

The previous prime is 13141030444097. The next prime is 13141030444121. The reversal of 13141030444103 is 30144403014131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13141030444103 - 214 = 13141030427719 is a prime.

It is a super-2 number, since 2×131410304441032 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13141030444123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570515222051 + 6570515222052.

It is an arithmetic number, because the mean of its divisors is an integer number (6570515222052).

Almost surely, 213141030444103 is an apocalyptic number.

13141030444103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141030444103 is an equidigital number, since it uses as much as digits as its factorization.

13141030444103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13141030444103 its reverse (30144403014131), we get a palindrome (43285433458234).

The spelling of 13141030444103 in words is "thirteen trillion, one hundred forty-one billion, thirty million, four hundred forty-four thousand, one hundred three".