13141042302433 has 2 divisors, whose sum is σ = 13141042302434. Its totient is φ = 13141042302432.

The previous prime is 13141042302397. The next prime is 13141042302469. The reversal of 13141042302433 is 33420324014131.

It is a balanced prime because it is at equal distance from previous prime (13141042302397) and next prime (13141042302469).

It can be written as a sum of positive squares in only one way, i.e., 9545949481104 + 3595092821329 = 3089652^2 + 1896073^2 .

It is an emirp because it is prime and its reverse (33420324014131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13141042302433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13141042302395 and 13141042302404.

It is not a weakly prime, because it can be changed into another prime (13141042302133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570521151216 + 6570521151217.

It is an arithmetic number, because the mean of its divisors is an integer number (6570521151217).

Almost surely, 2^{13141042302433} is an apocalyptic number.

It is an amenable number.

13141042302433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141042302433 is an equidigital number, since it uses as much as digits as its factorization.

13141042302433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13141042302433 its reverse (33420324014131), we get a palindrome (46561366316564).

The spelling of 13141042302433 in words is "thirteen trillion, one hundred forty-one billion, forty-two million, three hundred two thousand, four hundred thirty-three".