131411023212040 has 128 divisors (see below), whose sum is σ = 347393471846400. Its totient is φ = 44106530872320.

The previous prime is 131411023211999. The next prime is 131411023212097. The reversal of 131411023212040 is 40212320114131.

131411023212040 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 131411023211996 and 131411023212014.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 72486489 + ... + 74277271.

It is an arithmetic number, because the mean of its divisors is an integer number (2714011498800).

Almost surely, 2^{131411023212040} is an apocalyptic number.

131411023212040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131411023212040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173696735923200).

131411023212040 is an abundant number, since it is smaller than the sum of its proper divisors (215982448634360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131411023212040 is a wasteful number, since it uses less digits than its factorization.

131411023212040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1803647 (or 1803643 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131411023212040 its reverse (40212320114131), we get a palindrome (171623343326171).

The spelling of 131411023212040 in words is "one hundred thirty-one trillion, four hundred eleven billion, twenty-three million, two hundred twelve thousand, forty".