131411121004003 has 2 divisors, whose sum is σ = 131411121004004. Its totient is φ = 131411121004002.

The previous prime is 131411121004001. The next prime is 131411121004013. The reversal of 131411121004003 is 300400121114131.

It is a weak prime.

It is an emirp because it is prime and its reverse (300400121114131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131411121004003 - 2¹ = 131411121004001 is a prime.

It is a super-3 number, since 3×131411121004003³ (a number of 43 digits) contains 333 as substring.

Together with 131411121004001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131411121004001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705560502001 + 65705560502002.

It is an arithmetic number, because the mean of its divisors is an integer number (65705560502002).

Almost surely, 2^{131411121004003} is an apocalyptic number.

131411121004003 is a deficient number, since it is larger than the sum of its proper divisors (1).

131411121004003 is an equidigital number, since it uses as much as digits as its factorization.

131411121004003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 131411121004003 its reverse (300400121114131), we get a palindrome (431811242118134).

The spelling of 131411121004003 in words is "one hundred thirty-one trillion, four hundred eleven billion, one hundred twenty-one million, four thousand, three".