Base | Representation |
---|---|
bin | 111101001100010111… |
… | …0000011111000000011 |
3 | 110120012021102011112102 |
4 | 1322120232003320003 |
5 | 4123112233331321 |
6 | 140211450421015 |
7 | 12331331012102 |
oct | 1723056037003 |
9 | 416167364472 |
10 | 131411230211 |
11 | 50805239298 |
12 | 2157543176b |
13 | c513385ab1 |
14 | 6508aa2039 |
15 | 3641bc5c0b |
hex | 1e98b83e03 |
131411230211 has 2 divisors, whose sum is σ = 131411230212. Its totient is φ = 131411230210.
The previous prime is 131411230177. The next prime is 131411230213. The reversal of 131411230211 is 112032114131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131411230211 is a prime.
It is a super-2 number, since 2×1314112302112 (a number of 23 digits) contains 22 as substring.
Together with 131411230213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131411230213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705615105 + 65705615106.
It is an arithmetic number, because the mean of its divisors is an integer number (65705615106).
Almost surely, 2131411230211 is an apocalyptic number.
131411230211 is a deficient number, since it is larger than the sum of its proper divisors (1).
131411230211 is an equidigital number, since it uses as much as digits as its factorization.
131411230211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131411230211 its reverse (112032114131), we get a palindrome (243443344342).
The spelling of 131411230211 in words is "one hundred thirty-one billion, four hundred eleven million, two hundred thirty thousand, two hundred eleven".
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