Base | Representation |
---|---|
bin | 10011000111110111010… |
… | …011110110011100111000 |
3 | 11122121221212201011200011 |
4 | 103013313103312130320 |
5 | 133012301213421100 |
6 | 2443410135551304 |
7 | 163640655260530 |
oct | 23076723663470 |
9 | 4577855634604 |
10 | 1314114201400 |
11 | 467349231650 |
12 | 19282622b534 |
13 | 96bc727cac0 |
14 | 47863cac4c0 |
15 | 242b30b5bba |
hex | 131f74f6738 |
1314114201400 has 192 divisors, whose sum is σ = 4102242439680. Its totient is φ = 378086745600.
The previous prime is 1314114201377. The next prime is 1314114201437. The reversal of 1314114201400 is 41024114131.
It is a super-2 number, since 2×13141142014002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3081804 + ... + 3482203.
It is an arithmetic number, because the mean of its divisors is an integer number (21365846040).
Almost surely, 21314114201400 is an apocalyptic number.
1314114201400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1314114201400 is an abundant number, since it is smaller than the sum of its proper divisors (2788128238280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314114201400 is a wasteful number, since it uses less digits than its factorization.
1314114201400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6564054 (or 6564045 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 1314114201400 its reverse (41024114131), we get a palindrome (1355138315531).
The spelling of 1314114201400 in words is "one trillion, three hundred fourteen billion, one hundred fourteen million, two hundred one thousand, four hundred".
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