13141151352431 has 2 divisors, whose sum is σ = 13141151352432. Its totient is φ = 13141151352430.

The previous prime is 13141151352403. The next prime is 13141151352451. The reversal of 13141151352431 is 13425315114131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13141151352431 is a prime.

It is a super-2 number, since 2×13141151352431² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13141151352391 and 13141151352400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13141151352401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570575676215 + 6570575676216.

It is an arithmetic number, because the mean of its divisors is an integer number (6570575676216).

Almost surely, 2^{13141151352431} is an apocalyptic number.

13141151352431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141151352431 is an equidigital number, since it uses as much as digits as its factorization.

13141151352431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21600, while the sum is 35.

Adding to 13141151352431 its reverse (13425315114131), we get a palindrome (26566466466562).

The spelling of 13141151352431 in words is "thirteen trillion, one hundred forty-one billion, one hundred fifty-one million, three hundred fifty-two thousand, four hundred thirty-one".