13141151352643 has 2 divisors, whose sum is σ = 13141151352644. Its totient is φ = 13141151352642.

The previous prime is 13141151352583. The next prime is 13141151352757. The reversal of 13141151352643 is 34625315114131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13141151352643 - 2²¹ = 13141149255491 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13141151352596 and 13141151352605.

It is not a weakly prime, because it can be changed into another prime (13141151332643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570575676321 + 6570575676322.

It is an arithmetic number, because the mean of its divisors is an integer number (6570575676322).

Almost surely, 2^{13141151352643} is an apocalyptic number.

13141151352643 is a deficient number, since it is larger than the sum of its proper divisors (1).

13141151352643 is an equidigital number, since it uses as much as digits as its factorization.

13141151352643 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 40.

Adding to 13141151352643 its reverse (34625315114131), we get a palindrome (47766466466774).

The spelling of 13141151352643 in words is "thirteen trillion, one hundred forty-one billion, one hundred fifty-one million, three hundred fifty-two thousand, six hundred forty-three".