Base | Representation |
---|---|
bin | 1011111100111010100110… |
… | …1010001000011100000111 |
3 | 1201112021121102200011211221 |
4 | 2333032221222020130013 |
5 | 3210301034221240313 |
6 | 43540543411541211 |
7 | 2524262660323642 |
oct | 277165152103407 |
9 | 51467542604757 |
10 | 13141151352583 |
11 | 42071493930a1 |
12 | 1582a14bba807 |
13 | 744288c3b017 |
14 | 33606c51ca59 |
15 | 17bc714d4c8d |
hex | bf3a9a88707 |
13141151352583 has 2 divisors, whose sum is σ = 13141151352584. Its totient is φ = 13141151352582.
The previous prime is 13141151352541. The next prime is 13141151352643. The reversal of 13141151352583 is 38525315114131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141151352583 - 221 = 13141149255431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141151352503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570575676291 + 6570575676292.
It is an arithmetic number, because the mean of its divisors is an integer number (6570575676292).
Almost surely, 213141151352583 is an apocalyptic number.
13141151352583 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141151352583 is an equidigital number, since it uses as much as digits as its factorization.
13141151352583 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 216000, while the sum is 43.
The spelling of 13141151352583 in words is "thirteen trillion, one hundred forty-one billion, one hundred fifty-one million, three hundred fifty-two thousand, five hundred eighty-three".
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