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131412310323989 is a prime number
BaseRepresentation
bin11101111000010011010000…
…000100110111001100010101
3122020021220010212001100002012
4131320103100010313030111
5114211024402420331424
61143253552033354005
736452140361324102
oct3570232004671425
9566256125040065
10131412310323989
11389657142a20a2
12128a4704a08905
1358431876c7826
1424645656c5aa9
15102d508326b0e
hex7784d0137315

131412310323989 has 2 divisors, whose sum is σ = 131412310323990. Its totient is φ = 131412310323988.

The previous prime is 131412310323929. The next prime is 131412310324013. The reversal of 131412310323989 is 989323013214131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81892237621489 + 49520072702500 = 9049433^2 + 7037050^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131412310323989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131412310323929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706155161994 + 65706155161995.

It is an arithmetic number, because the mean of its divisors is an integer number (65706155161995).

Almost surely, 2131412310323989 is an apocalyptic number.

It is an amenable number.

131412310323989 is a deficient number, since it is larger than the sum of its proper divisors (1).

131412310323989 is an equidigital number, since it uses as much as digits as its factorization.

131412310323989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 839808, while the sum is 50.

The spelling of 131412310323989 in words is "one hundred thirty-one trillion, four hundred twelve billion, three hundred ten million, three hundred twenty-three thousand, nine hundred eighty-nine".