Base | Representation |
---|---|
bin | 11101111000010011010101… |
… | …011100001011001010000111 |
3 | 122020021220101010101122222201 |
4 | 131320103111130023022013 |
5 | 114211030043440234114 |
6 | 1143254005010335331 |
7 | 36452142533305366 |
oct | 3570232534131207 |
9 | 566256333348881 |
10 | 131412400321159 |
11 | 38965760081321 |
12 | 128a472ab8a547 |
13 | 58431a02483a9 |
14 | 24645736317dd |
15 | 102d5111a2874 |
hex | 7784d570b287 |
131412400321159 has 2 divisors, whose sum is σ = 131412400321160. Its totient is φ = 131412400321158.
The previous prime is 131412400321151. The next prime is 131412400321217. The reversal of 131412400321159 is 951123004214131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131412400321159 - 23 = 131412400321151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131412400321151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706200160579 + 65706200160580.
It is an arithmetic number, because the mean of its divisors is an integer number (65706200160580).
Almost surely, 2131412400321159 is an apocalyptic number.
131412400321159 is a deficient number, since it is larger than the sum of its proper divisors (1).
131412400321159 is an equidigital number, since it uses as much as digits as its factorization.
131412400321159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 131412400321159 in words is "one hundred thirty-one trillion, four hundred twelve billion, four hundred million, three hundred twenty-one thousand, one hundred fifty-nine".
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