Base | Representation |
---|---|
bin | 11101111000010011010101… |
… | …011100001011001011011011 |
3 | 122020021220101010101200002211 |
4 | 131320103111130023023123 |
5 | 114211030043440234433 |
6 | 1143254005010335551 |
7 | 36452142533305546 |
oct | 3570232534131333 |
9 | 566256333350084 |
10 | 131412400321243 |
11 | 38965760081398 |
12 | 128a472ab8a5b7 |
13 | 58431a0248442 |
14 | 246457363185d |
15 | 102d5111a28cd |
hex | 7784d570b2db |
131412400321243 has 2 divisors, whose sum is σ = 131412400321244. Its totient is φ = 131412400321242.
The previous prime is 131412400321217. The next prime is 131412400321259. The reversal of 131412400321243 is 342123004214131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131412400321243 is a prime.
It is not a weakly prime, because it can be changed into another prime (131412400325243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706200160621 + 65706200160622.
It is an arithmetic number, because the mean of its divisors is an integer number (65706200160622).
Almost surely, 2131412400321243 is an apocalyptic number.
131412400321243 is a deficient number, since it is larger than the sum of its proper divisors (1).
131412400321243 is an equidigital number, since it uses as much as digits as its factorization.
131412400321243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131412400321243 its reverse (342123004214131), we get a palindrome (473535404535374).
The spelling of 131412400321243 in words is "one hundred thirty-one trillion, four hundred twelve billion, four hundred million, three hundred twenty-one thousand, two hundred forty-three".
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