Base | Representation |
---|---|
bin | 11101111000010011010101… |
… | …011110111000111110110111 |
3 | 122020021220101011201211122111 |
4 | 131320103111132320332313 |
5 | 114211030044131030033 |
6 | 1143254005033511451 |
7 | 36452142542332216 |
oct | 3570232536707667 |
9 | 566256334654574 |
10 | 131412401033143 |
11 | 3896576051823a |
12 | 128a472b272587 |
13 | 58431a0437499 |
14 | 246457377907d |
15 | 102d5112937cd |
hex | 7784d57b8fb7 |
131412401033143 has 2 divisors, whose sum is σ = 131412401033144. Its totient is φ = 131412401033142.
The previous prime is 131412401033117. The next prime is 131412401033167. The reversal of 131412401033143 is 341330104214131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131412401033143 - 241 = 129213377777591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131412401033183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706200516571 + 65706200516572.
It is an arithmetic number, because the mean of its divisors is an integer number (65706200516572).
Almost surely, 2131412401033143 is an apocalyptic number.
131412401033143 is a deficient number, since it is larger than the sum of its proper divisors (1).
131412401033143 is an equidigital number, since it uses as much as digits as its factorization.
131412401033143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131412401033143 its reverse (341330104214131), we get a palindrome (472742505247274).
The spelling of 131412401033143 in words is "one hundred thirty-one trillion, four hundred twelve billion, four hundred one million, thirty-three thousand, one hundred forty-three".
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