Base | Representation |
---|---|
bin | 1011111100111010111100… |
… | …0001101101110110111010 |
3 | 1201112021211201011010211012 |
4 | 2333032233001231312322 |
5 | 3210301230300434432 |
6 | 43541000350233522 |
7 | 2524265133023534 |
oct | 277165701556672 |
9 | 51467751133735 |
10 | 13141241421242 |
11 | 4207195211000 |
12 | 1582a3b1b58a2 |
13 | 7442a17b529c |
14 | 33607a486854 |
15 | 17bc79376cb2 |
hex | bf3af06ddba |
13141241421242 has 16 divisors (see below), whose sum is σ = 21681567368064. Its totient is φ = 5973291553900.
The previous prime is 13141241421239. The next prime is 13141241421247. The reversal of 13141241421242 is 24212414214131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 13141241421199 and 13141241421208.
It is not an unprimeable number, because it can be changed into a prime (13141241421247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2468299634 + ... + 2468304957.
It is an arithmetic number, because the mean of its divisors is an integer number (1355097960504).
Almost surely, 213141241421242 is an apocalyptic number.
13141241421242 is a deficient number, since it is larger than the sum of its proper divisors (8540325946822).
13141241421242 is an equidigital number, since it uses as much as digits as its factorization.
13141241421242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4936604626 (or 4936604604 counting only the distinct ones).
The product of its digits is 12288, while the sum is 32.
Adding to 13141241421242 its reverse (24212414214131), we get a palindrome (37353655635373).
The spelling of 13141241421242 in words is "thirteen trillion, one hundred forty-one billion, two hundred forty-one million, four hundred twenty-one thousand, two hundred forty-two".
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