Base | Representation |
---|---|
bin | 1011111100111010111110… |
… | …0110110110000010000111 |
3 | 1201112021212101110121201202 |
4 | 2333032233212312002013 |
5 | 3210301240243412210 |
6 | 43541001335013115 |
7 | 2524265311531223 |
oct | 277165746660207 |
9 | 51467771417652 |
10 | 13141251154055 |
11 | 420719a759452 |
12 | 1582a4250a19b |
13 | 7442a381234b |
14 | 33607b89b783 |
15 | 17bc7a14a9a5 |
hex | bf3af9b6087 |
13141251154055 has 8 divisors (see below), whose sum is σ = 15769561468752. Its totient is φ = 10512960867328.
The previous prime is 13141251154049. The next prime is 13141251154063. The reversal of 13141251154055 is 55045115214131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13141251154055 - 26 = 13141251153991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3523514 + ... + 6220743.
It is an arithmetic number, because the mean of its divisors is an integer number (1971195183594).
Almost surely, 213141251154055 is an apocalyptic number.
13141251154055 is a deficient number, since it is larger than the sum of its proper divisors (2628310314697).
13141251154055 is an equidigital number, since it uses as much as digits as its factorization.
13141251154055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10013985.
The product of its (nonzero) digits is 60000, while the sum is 38.
Adding to 13141251154055 its reverse (55045115214131), we get a palindrome (68186366368186).
The spelling of 13141251154055 in words is "thirteen trillion, one hundred forty-one billion, two hundred fifty-one million, one hundred fifty-four thousand, fifty-five".
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