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131413024033 is a prime number
BaseRepresentation
bin111101001100011010…
…0111001110100100001
3110120012101210022012021
41322120310321310201
54123113213232113
6140211553101441
712331352162644
oct1723064716441
9416171708167
10131413024033
1150806253a95
1221575b57881
13c513863425
14650900ba5b
153641e2c48d
hex1e98d39d21

131413024033 has 2 divisors, whose sum is σ = 131413024034. Its totient is φ = 131413024032.

The previous prime is 131413024019. The next prime is 131413024051. The reversal of 131413024033 is 330420314131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123887808529 + 7525215504 = 351977^2 + 86748^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131413024033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131413023989 and 131413024007.

It is not a weakly prime, because it can be changed into another prime (131413024013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706512016 + 65706512017.

It is an arithmetic number, because the mean of its divisors is an integer number (65706512017).

Almost surely, 2131413024033 is an apocalyptic number.

It is an amenable number.

131413024033 is a deficient number, since it is larger than the sum of its proper divisors (1).

131413024033 is an equidigital number, since it uses as much as digits as its factorization.

131413024033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 131413024033 its reverse (330420314131), we get a palindrome (461833338164).

The spelling of 131413024033 in words is "one hundred thirty-one billion, four hundred thirteen million, twenty-four thousand, thirty-three".